the unit vector along icap and jcap is....
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ax and ay...............,
Harshady:
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hey...
unit vector along (i+j) is i+ j)/i+j is magnitude of (i+ j) we know,
i and j are perpendicular to each other
So, li+jl =√i^2+j^2+2.l.j.cos9O%)
= √(1+1) = √2
hence, unit vector along (i+ j) is (i+ j)/ √2
thankyou
hope it's help ✌✌
unit vector along (i+j) is i+ j)/i+j is magnitude of (i+ j) we know,
i and j are perpendicular to each other
So, li+jl =√i^2+j^2+2.l.j.cos9O%)
= √(1+1) = √2
hence, unit vector along (i+ j) is (i+ j)/ √2
thankyou
hope it's help ✌✌
dhanyawad
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