Physics, asked by ramreddyrr73, 11 months ago

the unit vector in direction of 2i+√3j+√2k​

Answers

Answered by awaisanwar492
0

Answer:

2i+√3j+√2k / 3

Explanation:

r = r / lrl = 2i+√3j+√2k / √4+3+2 = 2i+√3j+√2k / 3

Answered by bhanuprakashreddy23
1

Answer:

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Explanation:

let a=2i+√3j+√2k

unit vector in the direction of a = a/[a]

=(2i+√3j√2k)/√(2^2+√3^2+√2^2)

=(2i+√3j+√2k)/√(4+3+2)

=(2i+√3j+√2k)/√9

=(2i+√3j+√2k)/3

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