the unit vector in direction of 2i+√3j+√2k
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Answer:
2i+√3j+√2k / 3
Explanation:
r = r / lrl = 2i+√3j+√2k / √4+3+2 = 2i+√3j+√2k / 3
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Explanation:
let a=2i+√3j+√2k
unit vector in the direction of a = a/[a]
=(2i+√3j√2k)/√(2^2+√3^2+√2^2)
=(2i+√3j+√2k)/√(4+3+2)
=(2i+√3j+√2k)/√9
=(2i+√3j+√2k)/3
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