Question

The unit vector is represented by 0.5i+0.8j+ck then value of c is

Answer 1

Unit vector means the magnitude is = 1.
So 0.5^2 + 0.8^2 + c^2 = 1^2
c^2 = 1- 0.89
c = sqrt(0.11)

Answer 2

Answer:

root over 0.11

Explanation:

=> \sqrt{ {0.5}^{2} + ( { - 0.8}^{2} + {c}^{2} } = 1

=> {0.5}^{2} + {( - 0.8)}^{2} + {c}^{2} = 1

=>0.25 + 0.64 + {c}^{2} 1

=>0.89 + {c}^{2} = 1

=> {c}^{2} = 1 - 0.89

=> {c}^{2} = 0.11

=>c = \sqrt{0.11}