Physics, asked by rs2100, 10 months ago

The unit vector of a vector Ā=2i+3j +4K is
(1)9/root29(i+j+k) (2) root29 (2î +3j+ 4k)
c)1/root29 (2i +3j+ 4k) (4) 9root29(i + j+k)

Answers

Answered by PegasusPurpose
3

 \:\:\:\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \huge\mathcal{\bf{\underline{\underline{\huge\mathcal{Answer}}}}}

\large\mathcal\red{solution}

the unit vector is .....

 =  \frac{2i + 3j + 4k}{ \sqrt{2 {}^{2} + 3 {}^{2}  + 4 {}^{2}  }  }  \\  =\frac{2i + 3j + 4k}{ \sqrt{29} }  \\  =  \frac{2}{ \sqrt{29} } i +  \frac{3}{ \sqrt{29} } j +  \frac{4}{ \sqrt{29} }k  \\  =  \frac{1}{ \sqrt{29} } (2i + 3j + 4k)

\large\mathcal\red{hope\: this \: helps \:you......}

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