Question

The unit weight of the soil in uniform deposit of loose sand (k0=.50) is 18kN/m3 the geostratic stresses at depth of 3m will be

Answer 1

Explanation:

SORRY forgive me and Follow me please

Answer 2

Therefore the Geometric stress at the depth of 3 m of the loose sand is 27 KN/m².

Given:

Stress concentration factor = k₀ = 0.5

The weight of the soil in the uniform deposit of loose sand = 18 KN/m³

Depth = 3 m

To Find:

The geometric stresses at the depth of 3 m.

Solution:

The given question can be solved very easily as shown below.

Nominal Stress = σ₀ = ( Weight of the soil per unit volume ) × ( Depth )

⇒ Nominal Stress = σ₀ = 18 × 3 = 54 KN/m²

Now Geometric stress = ( Nominal Stress ) × ( Stress Concentration Factor )

⇒ Geometric stress = σ₀ × k₀ = 54 × 0.5 = 27 KN/m²

Therefore the Geometric stress at the depth of 3 m of the loose sand is 27 KN/m².

#SPJ1