Question

the unites digit of a two digit number is 3 and seven time the sum of the digits is the number itself. find the number​

Answer 1

Answer:

Step-by-step explanation:

Let the tens digit be x

So the no. is 10x +3 = 7[ x + 3]

                    10x + 3 = 7x + 21

                    10x - 7x = 21 - 3

                     3x = 18

                   X=6

So the number is 10*6+3

                            60+3

                            63

So the number is 63

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Answer 2

Answer:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.