Question

. The units digit is three times the tens digit of a two-digit number. When the digits are reversed,we get 36 more
than the number. Find the original number.
​

Answer 1

$\bold{\huge{\underline{\boxed{\sf{\green{ANSWER\::}}}}}}$

Given:

The units digit is three times the tens digit of a two- digit number.When the digits are reversed, we get 36 more than the number.

To find:

The original number.

$\bf{\large{\underline{\boxed{\rm{\red{Explanation\:}}}}}}$

Let the place of unit's digit be R &

Let the place of ten's digit be M

According to the question:

→ M = 3R.......................(1)

Let the original number= 10M+R

The reversed number= 10R+M

When the digits are reversed, we get 36 more than the original number;

→ 10M + R = 10R + M +36

→ 10M - M + R - 10R = 36

→ 9M - 9R = 36

→ 9(M - R) = 36

→ M - R= $\cancel{\frac{36}{9} }$

→ M - R = 4.....................(2)

Putting the value of M in equation (2), we get;

→ 3R - R = 4

→ 2R = 4

→ R = $\cancel{\frac{4}{2} }$

→ R = 2

Putting the value of R in equation (1),we get;

→ M = 3(2)

→ M = 6

Thus,

The original number is 10(6) + 2

The original number is 60+2 = 62.