the units digit of 2 digit numner is 3 and sewen times the sum of the digits is the no itself. find the no.
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let the digit in the ten's place be x
so the no. is- 10x+3
by the problem-
7(x+3)=10x+3
7x+21=10x+3
3x=18
x=6
the no- 6*10+3
=63
so the no. is- 10x+3
by the problem-
7(x+3)=10x+3
7x+21=10x+3
3x=18
x=6
the no- 6*10+3
=63
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