Question

The units digit of a 2-digit no. is 3 and seven times the sum of the digits is the number itself. Find the number.

Answer 1

Let the tens digit be x
So the no. is 10x +3 = 7[ x + 3]
                   3x = 18
                    X=6

So the number is 10*6+3
                             60+3
                             63

So the number is 63.

Hope this helps u..............^_^

Answer 2

✩Solution✩

✩Let the tens digit of the

   2-digit number be 'y'.

                                               

So, the number will be

10y + 3

                                           

✩ According to the question,

$7(y+3)=10y+3\\\\\implies7y+21=10y+3\\\\\implies21-3=10y-7y\\\\\implies18-3y\\\\\implies y=6$

                                             

✩Now we get the value of

  'y' as 6

So,

⇒ 10y + 3

= 10 × 6 +3

= 60 + 3

= 63

                                             

✩ So, the number is 63