Question

The units digit of a 2-digit number is 2. The number is eight times the sum of the digits. Find the number.​

Answer 1

Let the tens digit of the no. be x,
Units digit of the no. = 2
No. = 10(x) + 2
= 10x + 2
Sum of digits of the no. = x+2
No. = 8(sum of the no.s digits)
10x+2 = 8(x+2)
10x+2 = 8x + 16
10x -8x = 16 - 2
2x = 14
x = 14/2
x= 7
No. = 10(7) + 2
70 + 2
72
Hope it helps you!!!!!!!!!!!!!

Answer 2

Answer:

here your answer...................

72.

Step-by-step explanation:

let the two digit number be

10x+y

here

10x is tenth digit

y is unit's digit

According to question

y=2

and

8(x+y) =(10x+y)

put y=2

8(x+2) =10x+2

8x+16=10x+2

2x=14

x=7

therefore the number is

10x+y=10*7+2=70+2=72.