The units digit of a 2-digit number is 3.The number is seven times the sum of digits.Find the number.
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Unit digit of a two digit no = 3
Let digit at tens place be x
Two digit No. = 10 * tens place + 1 * ones place
= 10x+3
7(x + 3) =10x + 3
7x + 21 = 10x+3
21-3 = 10x-7x
x=18/3
x=6
Two digit no = 10*6+3
= 60+3
= 63
Let digit at tens place be x
Two digit No. = 10 * tens place + 1 * ones place
= 10x+3
7(x + 3) =10x + 3
7x + 21 = 10x+3
21-3 = 10x-7x
x=18/3
x=6
Two digit no = 10*6+3
= 60+3
= 63
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