The units digit of a two-digit number is 1 less than its tens digit. The sum of the number when digits are reversed and the original number is 77. Find the original number.
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Let the digit in the units place be x
Hence the digit in the tens place is (x+5)
The original number =10(x+5)+x=11x+50
Number formed by reversing the digits =10x+(x+5)=11x+5
Given that:- (11x+50)+(11x+5)=99
⇒22x+55=99
⇒22x=99−55=44
⇒x=2
∴ Original number =11x+50=11(2)+50=72
Hence the original number is 72.
Hence the correct answer is 72.
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