the units digit of a two digit number is 3 and 7 times the sum of the digits is the number itself find the number
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the units digit of a two digit number is 3 and 7 times the sum of the digits is the number itself find the number
is given that unit digit is 3 of a two digit number.
Let tens digit of a two digit number be x.
The number is 10x + 3
Sum of two digits = x + 3
According to the question,
7(x + 3) = 10x + 3
Solving this we get
x = 6
Hence the two digit number is 63.
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