Question

the units digit of a two- digit number is 3 and seven times the sum of the digits is the number itself. find the number​

Answer 1

Answer:

hi mate

let the digits be x and y let the unit digit b y let the number be 10 x + y now

7(x+y)=10x+y

7x+7y=10x+y

since y is equal to 3

therefore 7 x + 21 is equal to 10 x + 3

21 - 3 is equal to 10x minus 7 x

x is equals to 6

since the number was 10 x + y

and x=6

y=3

no is equal to 10x+y

that is equal to 10*6+3=63

Step-by-step explanation:

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Answer 2

Answer:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.