the units digit of a two digit number is 3 and seven times the sum of digit is number itself. find the number
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the no is 93 as S3 be the no so if we see table of 7 there is only one time unit digit of a no Comes 3 that is 7*9 = 63 So S = 9
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1
Step-by-step explanation:
- Unit of two digit number is 3
- Let the tens digit number be x
- The Number will be 10x + 3
- Sum of two digit number = x + 3
According to the question now :
➳ 7(x + 3) = 10x + 3
➳ 7x + 21 = 10x + 3
➳ 21 - 3 = 10x - 7x
➳ 18 = 3x
➳ x = 18/3
➳ x = 6
Therefore, the tens digit number is 6.
Hence,
The required number = 10x + 3 = 10(6) + 3 = 63.
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