Question

the units digit of a two digit number is 3 and seven times the sum of digit is number itself. find the number

Answer 1

the no is 93 as S3 be the no so if we see table of 7 there is only one time unit digit of a no Comes 3 that is 7*9 = 63 So S = 9

Answer 2

Step-by-step explanation:

• Unit of two digit number is 3

• Let the tens digit number be x

• The Number will be 10x + 3

• Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.