the units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself. find the number.
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The unit digit of a two-digit number is 3
u = 3
and seven times the sum of the digits is the number itself.
7(t+u) = 10t+u
Substitute 3 for u:
7(t+3) = 10t+3
7t+21 = 10t+3
-3t = -18
t = 6
The tens digit is 6 and the units digit is 3, so the number is 63.
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Answer:
The number is 63. 63 = 63. It's the only 2 - digit multiple of 7 with 3 as the units digit.
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