Question

the units digit of a two digit number is 3 and seven times the sum of the digits is the number itself. find the number ​

Answer 1

answer : required number is 63.

Answer 2

Answer:

Hello There,

This is your answer

Step-by-step explanation:

Let the tens digit be a and one's digit be b

b = 3 ( Given )

7 times the tens + unit digit = The number itself

7 ( a + b ) = 10a + b ( a is tens digit )

7 ( a + 3 ) = 10a + 3

7a + 21 = 10a + 3

21 - 3 = 10a - 7a

18 = 3a

a = 6

Hence, the number is 63.

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