Question

The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself.find the number​

Answer 1

Step-by-step explanation:

Given :-

The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself.

To find :-

Find the number ?

Solution :-

Given that

The units digit of a two digit number = 3

Let the tens digit of the two digit number be X

The place value of X = 10×X = 10X

Then ,

The number = 10X+3

Sum of the digits = X+3

Seven times the sum of the digits = 7(X+3)

=> 7X+21

According to the given problem

seven times the sum of the digits is the number itself.

=>7×Sum of the digits = the number

=> 7X+21 = 10X+3

=> 10X+3 = 7X+21

=> 10X-7X = 21-3

=> 3X = 18

=> X = 18/3

=> X = 6

Therefore,X = 6

The digit at tens place = 6

Answer:-

The required number for the given problem is 63

Check:-

The units digit = 3 (Given)

The tens digit = 6

7 times the sum of the digits = 7(6+3) = 7(9)=63

=> The number

seven times the sum of the digits is the number itself.

Verified the given relations in the given problem