Question

the units digit of a two digit number is 3 the number id seven times the sum of digits find the number

Answer 1

hey mate here is your answer ❤️❤️❤️❤️❤️

the digit in the unit place is 3. (given)

let the digit in the tens place be y

then, the number is 10y+3

(10y+3)=7(y+3)

10y+3=7y+21

3y-18=0

y=18/3

y=6

therefore the number is 10×6+3=63

hope it's helpful___________
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