Question

the units digit of a two digit number is 3 the number id seven times the sum of digits find the number

Answer 1

Sol: Units digit of a two digit number = 3 Let the tens digit of the number be x. Number = 10x + 3 Sum of the digits = (x + 3) Given that 7 times the sum of the digits is the number itself. ⇒ 7(x + 3) = (10x + 3) ⇒ 7x + 21 = 10x + 3 ⇒ 10x - 7x = 21 - 3 ⇒ 3x = 18 ⇒ x = 6. Therefore, the digits in the tens place is 6 and the number is 63.

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