Question

The units digit of a two number is 3 and seven times the sum of the digits is the number itself find the number

Answer 1

Given , units digit = 3
Let tens digit be x
Hence , no. = 10x+3
Sum of digits = (x+3)
10x+3 = 7(x+3)
3x=18
x=6
Hence , no. = 10(6)+3 = 63

Answer 2

Step-by-step explanation:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.