Question

the units digit of two digit number is 3 qnd seven times the sum of the digits is the number iiself. Find the number​

Answer 1

Answer:

We know that the unit place is 3

So let’s consider the tens place as y

So the equation is (10y + 3)……………..> Equation (1)

From the question, seven times the sum of the digits is the number itself

∴From the above condition, 7(y + 3)……….. Equation (2)

Combining equation 1 and 2 we get,

7(y + 3) = (10y + 3)

7y + 21 = 10y + 3

7y -10y = 3 – 21

-3y = -18

∴ y = 6

Substituting the value of y in equation 1 we get,

10y + 3

10(6) + 3 = 60 + 3 = 63

∴ The required number is 63.

Answer 2

Answer:

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