Math, asked by EnchantedBoy, 8 months ago

the units digits in the product of (101)^101×(102)^(103)^103 is​

Answers

Answered by steffis
1

Unit digit of the product 101^{101}×102^{103^{103} } will be 4.

Step 1: Solve the equation by observation.

Given - 101^{101}×102^{103^{103} }

we can't solve this much lengthy values so, we will observe the last digits.

As we know that, 11^{11} = its last digit will be 1.

                            21^{21} = its last digit will also be 1.

so, by this observation we can understand that last digit of 101^{101} will also be 1.

similarly,

                103^{103} = last digit will be 7

so,          102^{ending with 7} = last digit will be 4

so, if we multiply their last digits as 1 and 4 we will get unit digit as 4.

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