The units place digit of a 2 digit no is twice the tens place digit. if the digits are reversed the no is 27 more than the original no. find the no
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Let the tens digit be x
Unit digit = y
Original no.= 10x+y
On reversing the digits =10y+x
A/q
10x+y +27 = 10y+x
10x+y-(10y+x) = -27
10x+y-10y-x = -27
9x-9y = -27
9(x-y) = -27
x-y = -27÷9
x-y = -3
-3 = x-y
y = x+3
If, x = 1
y = 1+3
no. = 14
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