Question

The units place digit of a 2 digit no is twice the tens place digit. if the digits are reversed the no is 27 more than the original no. find the no

Answer 1

Let the tens digit be x Unit digit = y Original no.= 10x+y On reversing the digits =10y+x A/q 10x+y +27 = 10y+x 10x+y-(10y+x) = -27 10x+y-10y-x = -27 9x-9y = -27 9(x-y) = -27 x-y = -27÷9 x-y = -3 -3 = x-y y = x+3 If, x = 1 y = 1+3 no. = 14