Question

the units place digit of a two digit number is 5 . the number

is 5 times the sum of the digits. find the number​

Answer 1

$Given \: Units \:place \:digit = 5$

$Let \: Ten's \:place \:digit = x$

$\pink { Original \: number } = 10x + 5 \:--(1)$

/* According to the problem given,

The number is 5 times the sum of the digits*/

$10x + 5 = 5( x + 5 )$

$\implies 10x + 5 = 5x + 25$

$\implies 10x - 5x = 25 - 5$

$\implies 5x = 20$

$\implies x = \frac{20}{5}$

$\implies x = 4$

/* Put x = 4 in equation (1) , we get */

$\pink { Original \: number } \\= 10\times 4 + 5\\= 40 + 5 \\= 45$

Therefore.,

$\pink { Original \: number }\green {= 45 }$

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