Math, asked by chithru28cv, 8 months ago

the universal sets of sets a={x:x^2-5x+6=0} and b={x:x^2-3x+2=0} having least number of elements is​

Answers

Answered by hanshu1234
4

Step-by-step explanation:

Given U={x∣x5−6x4+11x3−6x2=0}

x5−6x4+11x3−6x2=0

x2(x3−6x2+11x−6)=0

x2(x2−5x+6)(x−1)=0

x2(x−3)(x−2)(x−1)=0

Hence U={0,1,2,3}

A={x∣x2−5x+6=0}

x2−5x+6=0

(x−3)(x−2)=0

Hence A={2,3}

B={x∣x2−3x+2=0}

x2−3x+2=0

(x−2)(x−1)=0

B={1,2}

A∩B={2}

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