Math, asked by renuvasan1999, 8 months ago

The unknown coefficient of the equation x^2 +bx+3=0 is determined by throwing an ordinary six faced die. The probability of that equation has real roots is

Answers

Answered by areejhunzla14
1

Answer:

sorry

I don't know plz sorry

Answered by ushmagaur
1

Answer:

The probability of getting that equation has real roots is \frac{1}{2}.

Step-by-step explanation:

For a quadratic equation, ax^2+bx+c=0, the expression b^2-4ac is called the discriminant.

If the value of discriminant b^2-4ac > 0, then the quadratic equation has two distinct real roots.

If the value of discriminant b^2-4ac =0, then the quadratic equation has repeated real roots.

Consider the quadratic equation as follows:

x^2+bx+3=0 ...... (1)

Here, a=1, b=b and c=3

Then discriminant is

b^2-4ac=b^2-4(1)(3)

             =b^2-12

A die is thrown. Then sample will be

S = {1, 2, 3, 4, 5, 6}

According to the question, probability that the equation (1) has real root

So, either b^2-12=0 or b^2-12 > 0.

Case1. If b^2-12=0.

b^2=12

b=2\sqrt{3}, which is not possible.

As 2\sqrt{3} is not in the sample space.

Case2. If b^2-12 > 0.

b^2 > 12

Then, for b=4,5,6.The expression b^2 > 12 holds.

Thus, probability of getting real roots = \frac{3}{6}

                                                                = \frac{1}{2}.

#SPJ3

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