Question

The upper end of a wire of diameter 12mm and length 1m is clamped and its other end is twisted through an angle of 30°. The angle of shear is (a) 18° (b) 0.18° (c) 36° (d) 0.36°

Answer 1

Answer:

B

Explanation:

Given Data:

diameter=12mm

convert it to radius ,

r=d/2=12/2=6mm

rθ=lФ

Ф=rθ/l

=6mm $30^{0}$/1m

=$0.18^{0}$