Question

The upper end of a wire of radius 3 mm and length 2 m is clamped. If its other end is twisted through an angle of 30°, then angle of shear will be​

Answer 1

Thus the angle of shear is ϕ = 0.045°

Explanation:

We are given that:

• Radius of upper end = 3 mm = 0.3 cm
• Length of wire = 200 cm
• Angle = 30°
• To Find: Angle of shear

Solution:

According to the relation:

rθ = lϕ

ϕ = rθ / l

ϕ = 0.3 x 30 / 200

ϕ = 9 / 200 = 0.045°

Thus the angle of shear is ϕ = 0.045°

Answer 2

Answer:

0.16°

this is the answer