Question

The upper end of a wire of radius 4mm and length 100cm is clamped and its other end is twisted through an angle of 30 . then angle of shear is

Answer 1

Answer:

Explanation

r = 4m =  × $10^{-3}$ m

L=100 cm = $\frac{1}{10}$ m

Q = 30°

Ф=$\frac{rQ}{L}$  =4×$10^{-3}$×30/$\frac{1}{10}$ = 4×$10^-{2}$×30

= 120 ×$10^{-2}$ = 120×$10^{-3}$

= $\frac{120}$/$10^{3}$ = 0.12°