Question

The upper end of wire 1 m long and 2 mm radius is clamped. The lower end is twisted through an angle of 45°. The angle of shear is :-

Step By Step Explanation only..​

Answer 1

Given :-

Length of wire = L = 1 m

Radius of wire = r = 2 mm = 2 × 10-³ m

Angle of twist = Ø = 45°

Now, Using the relation i.e.

r/L = ϵ⁰/Ø

ϵ⁰ = rØ/L

ϵ⁰ = 2 × 10-³ × 45°/1

ϵ⁰ = 90° × 10-³

ϵ⁰ = 0.09°

Henec,

The angle of Shear = ϵ⁰ = 0.09°

Answer 2

GIVEN:-

• Length of the wire is 1 metre.
• radius of the wire:-
• angle of twist is 45°.

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