The upper part of a straight tree broken by the wind makes an angle of 45° with the plane surface at a point 9m from the foot of the tree. find the height of the tree before it was broken.
Answers
Answered by
1
Step-by-step explanation:
AC IS THE BORKEN PART OF THE TREE and AB is the reminding part of the tree
We get a 45∘−45∘−90∘ triangle.
We get AB=BC=12m
AC2=AB2+BC2
⇒AC2=122+122=2×122
⇒AC=122m
Height of the tree=broken part+ remaining part
AC+AB=12+122=12(1+2)
Similar questions