Question

The upper part of a straight tree is broken by the wind and the makes an angle of 45% with the plain surface at a point 9m from the foot of the tree.Find the hight of tree before it was broken.

Answer 1

Answer:

12(1+√2)

Step-by-step explanation:

consider

The hypotnuse AC as the broken part of the tree. AB is the remaining part of the tree.

90+45+45=180 {ASP of triangle}

AB=AC= 12m

height of the tree =AC+BC

                             = 12+12√2

                             = 12(1+√2)