the upper part of a tree broken over by the wind make an angle of 60° with the ground and the horizontal distance from the foot of the tree to the point where the top of the tree meet tje ground is 10 meter fi d the height of the tree before broken
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let's take
tan 60°=√3
distance=10 m
so tan =perpendicular/base
so let perpendicular be h,
base 10(given)
tan 60°=h/10. √3=1.732
1.732×10=H
Therefore h =17.32 m
hope it may help you
good day
tan 60°=√3
distance=10 m
so tan =perpendicular/base
so let perpendicular be h,
base 10(given)
tan 60°=h/10. √3=1.732
1.732×10=H
Therefore h =17.32 m
hope it may help you
good day
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