the upper part of a tree broken over by the wind make an angle of 60° with the ground and horizontal distance from the foot of the tree to the point where the top of the tree meets the ground is 10 meter find the height of tree before broken
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ʜᴇy ʙᴜᴅᴅy
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ꜱᴇᴇ ᴛʜᴇ ꜰɪɢᴜʀᴇ ɪᴛ ꜰᴏʀᴍꜱ ᴀ ʀɪɢʜᴛ ᴀɴɢʟᴇᴅᴄ ᴛʀɪᴀɴɢʟᴇ .....
ᴛᴏᴛᴀʟ ʜᴇɪɢʜᴛ ᴏꜰ ᴛʜᴇ ʙᴇꜰᴏʀᴇ ʙʀᴏᴋᴇɴ=ᴩᴇʀᴩᴇɴᴅɪᴄᴜʟᴀʀ+ʜyᴩᴏᴛᴇɴᴜꜱᴇ
ɪᴇ. =ᴀᴄ+ʙᴄ
ᴄᴏꜱ60°=10/ʙᴄ
1/2=10/ʙᴄ
20=ʙᴄ
ʙy ᴩyᴛʜᴀɢᴏʀᴇᴏᴜꜱ ᴛʜᴇᴏʀᴀᴍ
(ʙᴄ)²=(ᴀᴄ)²+(ᴀʙ)²
(ᴀᴄ)²=(ʙᴄ)²-(ᴀʙ)²
=(20)²-(10)²
=400-100
=300
(ᴀᴄ)²=300
ᴀᴄ=√300
ᴀᴄ=10√3......
ᴛᴏᴛᴀʟ ʜᴇɪɢʜᴛ ᴏꜰ ᴛʀᴇᴇ ʙᴇꜰᴏʀᴇ ʙʀᴏᴋᴇɴ
=ᴀᴄ+ʙᴄ
=10√3+20
=10√3+20
=10×1.73+20
=17.3+20
=37.3
ᴛᴏᴛᴀʟ ʜᴇɪɢʜᴛ ᴏꜰ ᴛʜᴇ ᴛʀᴇᴇ ʙᴇꜰᴏʀᴇ ʙʀᴏᴋᴇɴ=37.3
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ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ
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ꜱᴇᴇ ᴛʜᴇ ꜰɪɢᴜʀᴇ ɪᴛ ꜰᴏʀᴍꜱ ᴀ ʀɪɢʜᴛ ᴀɴɢʟᴇᴅᴄ ᴛʀɪᴀɴɢʟᴇ .....
ᴛᴏᴛᴀʟ ʜᴇɪɢʜᴛ ᴏꜰ ᴛʜᴇ ʙᴇꜰᴏʀᴇ ʙʀᴏᴋᴇɴ=ᴩᴇʀᴩᴇɴᴅɪᴄᴜʟᴀʀ+ʜyᴩᴏᴛᴇɴᴜꜱᴇ
ɪᴇ. =ᴀᴄ+ʙᴄ
ᴄᴏꜱ60°=10/ʙᴄ
1/2=10/ʙᴄ
20=ʙᴄ
ʙy ᴩyᴛʜᴀɢᴏʀᴇᴏᴜꜱ ᴛʜᴇᴏʀᴀᴍ
(ʙᴄ)²=(ᴀᴄ)²+(ᴀʙ)²
(ᴀᴄ)²=(ʙᴄ)²-(ᴀʙ)²
=(20)²-(10)²
=400-100
=300
(ᴀᴄ)²=300
ᴀᴄ=√300
ᴀᴄ=10√3......
ᴛᴏᴛᴀʟ ʜᴇɪɢʜᴛ ᴏꜰ ᴛʀᴇᴇ ʙᴇꜰᴏʀᴇ ʙʀᴏᴋᴇɴ
=ᴀᴄ+ʙᴄ
=10√3+20
=10√3+20
=10×1.73+20
=17.3+20
=37.3
ᴛᴏᴛᴀʟ ʜᴇɪɢʜᴛ ᴏꜰ ᴛʜᴇ ᴛʀᴇᴇ ʙᴇꜰᴏʀᴇ ʙʀᴏᴋᴇɴ=37.3
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ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ
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