Question

The upper part of a tree is broken by wind and makes an angle of 30°with the ground.At the distance of 21 m from the foot of the tree.Find the height of the tree?

Answer 1

cos 30° = 21/x

x(Hypotenuse) = 42

tan 30° = y/21

$y \: opposite= 21/ \sqrt{3}$

Height of the tree = x + y

$= 42 + 21/ \sqrt{3}$

= 78.456 metres

Thank You..