The upper part of a tree is broken over by the wind makes an angle of 45degree with the ground if the horizontal distance from the root of the tree to the point where the top of the tree meets the ground is 6m find the height of the tree
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base makes an angle of 45 degree so
length of perpendicular = length of base = 6m
length of hypotenous = (6^2 +6^2)^.5 = 72^.5
= 6 root 2 m
so height of tree = hypotenous + perpendicular
= 6 root 2 + 6 = 6(root 2 +1) m
length of perpendicular = length of base = 6m
length of hypotenous = (6^2 +6^2)^.5 = 72^.5
= 6 root 2 m
so height of tree = hypotenous + perpendicular
= 6 root 2 + 6 = 6(root 2 +1) m
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