Math, asked by yugpokharel1, 1 month ago

the upper part of cylindrical tank is hemisphere. if height of tank is 9m circumference of base is 44m, how many litre can the tank hold?

Answers

Answered by poonam847211devi
7

Answer:

SINCE circumference of the base of the cylindrical tank is 44m.

so, C =44m

then, 2πr=44m

2×22/7×r=44

44/7r=44

so,r=44×7/44

hence r=7m

radius of the base of the cylindrical tank = radius at its top=7m

Thus, the volume of the hemispherical tank is given as,

V=2/3πr³

=2/3 ×22/7× 7³

=2/3 ×22/7 ×7×7×7

= 718.7m³( approx )

Now,

height of the hemispherical part lying above the cylindrical tank,h' =7m

Height of the cylindrical

tank +h'= 9m

so, height of the cylindrical tank = 9-h'

= 9-7= 2m

So. the volume of the cylindrical tank, v= πr²h'

v = 22/7 × 7×7×2

v= 308m³

hence ,total volume of the cylindrical tank with the hemispherical portion over it = V+v

= 718.7+308 m³

= 1026.7m³

Hence ,the given tank will hold water =

( 1026.7×1000)L=1026700L

I hope it will help you , if something is found to be a mistake so sorry for this

Answered by netra9716
0

Step-by-step explanation:

oh no

Similar questions