Question

:-The upper
surface of a table is like trapezium. The length
of the parallel sides of this table is 7 m and 9 m
and the distance between the parallel sides of
this table is 3 m. The area of the upper surface
of the table will be: -
24 वर्गमीटर Sq.Metre
48 वर्गमीटर Sq. Metre
24 मीटर Metre
32 वर्गमीटर Sq.Metre​

Answer 1

Let′s understand the question.

★ This question says that the parallel sides measure 7 m and 9 m. The distance between the two parallel sides is 3 m. We have to find out the area of trapizum..!

Let's solve this problem..!

$\large\underline{\sf{Given- }}$

A trapezium whose

• length of parallel sides measure 7 m and 9m

and

• distance between two parallel sides is 3 m.

$\large\underline{\sf{To\:Find - }}$

• Area of trapezium

$\large\underline{\sf{Solution-}}$

Given that,

• Length of one parallel side of trapezium = 7m

• Length of other parallel side of trapezium = 9 m

• Distance between two parallel sides = 3 m

We know that

$\rm :\longmapsto\:Area_{(trapezium)} = \dfrac{1}{2} (sum \: of \parallel \: sides) \times distance \: beween \: them$

$\rm :\longmapsto\:Area_{(trapezium)} = \dfrac{1}{2} \times (9 + 7) \times 3$

$\rm :\longmapsto\:Area_{(trapezium)} = \dfrac{1}{2} \times 16 \times 3$

$\bf\implies \:Area_{(trapezium)} = 24 \: {m}^{2}$

Additional Information :-

$\boxed{ \bf \: Area_{(square)} = {(side)}^{2}}$

$\boxed{ \bf \: Area_{(rectangle)} = length \times breadth}$

$\boxed{ \bf \: Area_{(circle)} = \pi \: {r}^{2}}$

$\boxed{ \bf \: Area_{(rhombus)} = base \times height}$

$\boxed{ \bf \: Area_{(parallelogram)} = base \times height}$