Question

The v. D of gas w.r.t ;methane is 4. Then the gas is

Answer 1

Answer:

The gas can be sulphur dioxide SO₂ having molar mass 64g

Explanation:

$\blacksquare$ Molar mass of methane (CH₄)

= 12 + 1*4

= 12 + 4

= 16g

$\blacksquare$ Hence,

Vapour density of gas w.r.t methane = $\dfrac{Molar \ mass}{16}$

$\blacksquare$ Given that,

V.D. w.r.t methane = 4

$\blacksquare$ Putting this value in we get,

4 = $\dfrac{Molar \ mass}{16}$

Molar mass = 4 * 16

Molar mass = 64 g

$\blacksquare$ We know that,

Molar mass of SO₂

= 32 + 16*2

= 32 + 32

= 64 g

$\blacksquare$ Hence, the gas can be sulphur dioxide (SO₂)