Question

the v-t graph of a particle moving along x-axis given above.then displacement and distance of the particle during two seconds from starting are (in metres)​

Answer 1

Given:

The v-t graph of a particle moving along x-axis given above.

To find:

The value of Displacement and Distance?

Calculation:

Displacement is defined as the shortest length between the starting and stopping point of the object.

$\therefore \: displacement = net \: area \: of \: v - t \: graph$

$\implies \: displacement = (1 \times 1) + \{( - 1) \times 1 \}$

$\implies \: displacement =1 - 1$

$\implies \: displacement =0 \: metres$

So, Displacement is zero.

Distance is defined as the path length traversed by an object.

$\therefore \: distance = total \: area \: of \: v - t \: graph$

$\implies \: distance = (1 \times 1) + (1 \times 1)$

$\implies \: distance = 1 + 1$

$\implies \: distance = 2 \: metres$

So, distance is 2 metres.

Answer 2

Given:

The v-t graph of a particle moving along x-axis given above.

To find:

Then displacement and distance of the particle during two seconds from starting are (in metres)​

Solution:

From given, we have the data as follows.

The v-t graph of a particle moving along x-axis

Displacement = vt

= (1 × 1) + (-1 × 1)

= 1 - 1

= 0

Distance = |v|t

= |(1 × 1)| + |(-1 × 1)|

= 1 + 1

= 2 m

Therefore, the displacement is 0 and the distance is 2 m.