The v-t graph of an object as shown below
Identify the type of motion by lines O A and B C
Velocity at equals to 8 seconds
Calculate acceleration between 3rd and 10th second last 2 seconds
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Explanation:
Motion represented by lines OA and BC are uniformly accelerated and uniformly decelerated motion respectively
the accelerations of the lift
(a) during the first two second ( from O-A )
a =v-u/t =4.6-0/2=2.3 m/s²
(b) between third and tenth second , the graph is the straight line parallel to the time axis hence acceleration =0
(c) during the last two second (from B-C)
a = v-u/t =0-4.6/2 = -2.3 m/s²
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