Chemistry, asked by shrikhakamath, 1 year ago

The valence electron in beryllium atomic number for experiences lower net of attraction to the nucleus compared to those of oxygen (atomic number 8) though both the atoms have same number of shells explain

Answers

Answered by DeveshPunjabi17
2

Explanation:

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The valence electrons in Be experience lower net attraction than those of oxygen due to lower nuclear charge in the case of Be.

The electronic configuration of Be is 1s²2s², whereas that of O is 1s²2s²2p⁴.

Hence, Be has 4 protons in the nucleus while oxygen has 8 protons.

So, even though both have electrons in the second shell, the 8 protons of oxygen pull it's valence electrons more prominently than the 4 protons of Be.

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Answered by dryash1009
0

Answer:

Explanation:

Atomic number of Beryllium = 4

Electronic configuration = (2, 2)

Atomic number of Oxygen = 8

Electronic configuration = (2, 6)

Valency of Beryllium is 2,

Valency of Oxygen is = 8 ‒ 6 = 2

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