The valency of sulphur in SO2 and SO3 is 4,6. Pls explain how?
Answers
Answer:
As we can recognize that in S02, the abundance of oxygen atoms is -2 and the valency of oxygen particle is 2. ... Accordingly, the valency of S will be +4. Furthermore, in the S03, the number of oxygen particles is 3. Thus, that provides us a valency of +6 on the sulfur.
The oxidation state of Sulphur in SO2 is +4. and of SO3 is +6
The rules to determine an oxidation number of sulphur in SO2 and SO3 -
1) Sum of all oxidation numbers in the neutral compound is zero.
2) The oxygen oxidation number in a compound is -2. If oxygen is in the class of compounds known as peroxides then oxygen will have oxidation number as –1, whereas If oxygen is bonded to fluorine, the number will be +1.
in SO2
Let state of oxidation of sulphur be = x
Oxygen oxidation state = -2 ( As per rule -2)
Total charge = 0 ( As per rule -1)
Equation = x + 2(-2) = 0
x - 4 = 0
x = 4
Thus, the oxidation state of Sulphur in SO2 is +4.
in SO3
Let oxidation state of sulphur be = y
Oxygen oxidation state = -2 ( As per rule -2)
Total charge = 0 ( As per rule -1)
Equation = y + 3(-2) = 0
y - 6 = 0
y = 6
Thus, the oxidation state of sulphur in SO3 is +6