Question

the valie of sin60 + cot45 - cosec30 / sec60 - cos30 + tan45​

Answer 1

Answer:

1

Explanation:

sin60= √3/2

cot45= 1

cosec30=2

sec60=2

cos30=√3/2

tan45= 1

√3/2 +1 - 2/2-√3/2+1= 1

Answer 2

The value of  $\frac{sin60 + cot45 - cosec30}{sec60 - cos30 + tan45}$ is $= \frac{\sqrt{3} - 2}{6 - \sqrt{3} }$.

Given:

Given, $\frac{sin60 + cot45 - cosec30}{sec60 - cos30 + tan45}.$

To Find:

We have to find the value of the expression $\frac{sin60 + cot45 - cosec30}{sec60 - cos30 + tan45}.$

Solution:

The value of given angles are:

sin 60° = $\frac{\sqrt{3} }{2}$.

cot 45° = $1$.

cosec 30° = $2$.

sec 60° = $2$.

cos 30° = $\frac{\sqrt{3} }{2}$.

tan 45° = $1$.

On substituting all these values in the given expression, we get,

$\frac{sin60 + cot45 - cosec30}{sec60 - cos30 + tan45}$ $= \frac{\frac{\sqrt{3} }{2} + 1 - 2}{2 - \frac{\sqrt{3} }{2} + 1}$

$= \frac{\sqrt{3} - 2}{6 - \sqrt{3} }$.

Hence, the value of $\frac{sin60 + cot45 - cosec30}{sec60 - cos30 + tan45}$ is $= \frac{\sqrt{3} - 2}{6 - \sqrt{3} }$.

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