Question

the value
f (x-y)=6 and xy = 10, find
(x²+ y²).​

Answer 1

$given: \\ \\ (x - y) = 6 \\ xy = 10 \\ \\ we \: know \: that \\ {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy \\ \\ {6}^{2} = {x}^{2} + {y}^{2} - 2(10) \\ \\ 36 = {x}^{2} + {y}^{2} - 20 \\ \\ 36 + 20 = {x}^{2} + {y}^{2} \\ \\ 56 = {x}^{2} + {y}^{2}$