Question

the value for k for which the system of equations kx-y=2 and 6x-2y=3 has a unique solution is _______​

Answer 1

Step-by-step explanation:

i didn't understand the question

Answer 2

$kx \: - y = 2 \\ kx - y - 2 = 0..............(1) \\ 6x - 2y = 3 \\ 6x - 2 - 3 = 0..............(2) \\ to \: have \: a \: unique \: solution \: the \: condition \: is \: \\ \frac{k}{6} \: should \: not \: be \: equal \: to \: \frac{ - 1}{ - 2} \\ \frac{k }{3} \: not \: equal \: to \: 1 \\ k \: is \: not \: equal \: to \: 3$

Hence, the required answer is k ≠ 3

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