Math, asked by Anonymous, 9 months ago

The value of 1/(√18-√32) is equal to:

Answers

Answered by shahid7655
5

Answer:

by rationalising

1/ √18 -√32 × √18+√32/√18+√32

= (√18+√32)/ (√18)²-(√32)²

= (√18+√32)/18-32

= (√18+√32)/-14

identity used-

(a-b)(a+b) = a²-b²

√18 = √2×3×3

= 3√2

√32 = √2×2×2×2×2

= 4√2

√18+√32

= 3√2+4√2

= 7√2

7√2/-14

= -√2/2

= -1/√2

option (d)

Answered by Ravkiratchampshooter
2

Answer

-5\sqrt{2}/14

Step-by-step explanation:

BY THE PROCESS OF RATIONALIZATION

=) 1 /root 18- root 32 x  root 18 + root 32/root 18 + root 32

=) root 18 + root 32/ (root 18)^2- (root 32)^2

=) root 18 + root 32/ 18-32

=) - root 50/14

=) \sqrt{2*5*5/14

=) -5\sqrt{2}/14

THIS IS THE ANSWER

HOPE IT HELPS!!!!!!!!!!

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