Question

the value of [{(-1/2)²}-²]-¹​

Answer 1

Answer:

1/16 is the ans

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Answer 2

Given,

An expression, $[({(-\frac{1}{2})^{2} )^{-2}]^{-1}$

To Find,

The value of the expression.

Solution,

We know that $x^{-1}$ = $\frac{1}{x}$.

We need to solve it step by step.

$[({(-\frac{1}{2})^{2} )^{-2}]^{-1}$

=$[({\frac{1}{4} )^{-2}]^{-1}$

=$[(\frac{1}{16} )^{-1}]^{-1}$

=$[\frac{16}{1} ]^{-1}$

=$\frac{1}{16}$.

Hence, the value of  $[({(-\frac{1}{2})^{2} )^{-2}]^{-1}$ is $\frac{1}{16}$.