the value of |(1+2i)(2-i)/3+4i| is equal to
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Answer:
(1+i)(1+2i)(1+3i)∣ = ∣1+i∣∣1+2i∣∣1+3i∣ (∵∣Z
1
Z
2
∣=∣Z
1
∣∣Z
2
∣)
=
2
⋅
5
⋅
10
∴∣(1+i)(1+2i)(1+3i)∣=10
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